Over a million developers have joined DZone.
{{announcement.body}}
{{announcement.title}}

Clojure: First Steps With Reducers

DZone's Guide to

Clojure: First Steps With Reducers

Here's a look at using Clojure, and getting started with reducers.

· Java Zone ·
Free Resource

How do you break a Monolith into Microservices at Scale? This ebook shows strategies and techniques for building scalable and resilient microservices.

I’ve been playing around with Clojure a bit today in preparation for a talk I’m giving next week and found myself writing the following code to apply the same function to three different scores:

(defn log2 [n]
  (/ (Math/log n) (Math/log 2)))

(defn score-item [n]
  (if (= n 0) 0 (log2 n)))

(+ (score-item 12) (score-item 13) (score-item 5)) 9.60733031374961

I’d forgotten about folding over a collection but quickly remembered that I could achieve the same result with the following code:

(reduce #(+ %1 (score-item %2)) 0 [12 13 5]) 9.60733031374961

The added advantage here is that if I want to add a 4th score to the mix all I need to do is append it to the end of the vector:

(reduce #(+ %1 (score-item %2)) 0 [12 13 5 6]) 12.192292814470767

However, while Googling to remind myself of the order of the arguments to reduce I kept coming across articles and documentation about reducers which I’d heard about but never used.

As I understand they’re used to achieve performance gains and easier composition of functions over collections so I’m not sure how useful they’ll be to me but I thought I’d give them a try.

Our first step is to bring the namespace into scope:

(require '[clojure.core.reducers :as r])

Now we can compute the same result using the reduce function:

(r/reduce #(+ %1 (score-item %2)) 0 [12 13 5 6]) 12.192292814470767

So far, so identical. If we wanted to calculate individual scores and then filter out those below a certain threshold the code would behave a little differently:

(->>[12 13 5 6]
    (map score-item)
    (filter #(> % 3))) (3.5849625007211565 3.700439718141092)

(->> [12 13 5 6]
     (r/map score-item)
     (r/filter #(> % 3))) #object[clojure.core.reducers$folder$reify__19192 0x5d0edf21 "clojure.core.reducers$folder$reify__19192@5d0edf21"]

Instead of giving us a vector of scores the reducers version returns a reducer which can pass into reduce or fold if we want an accumulated result or into if we want to output a collection. In this case, we want the latter:

(->> [12 13 5 6]
     (r/map score-item)
     (r/filter #(> % 3))
     (into [])) (3.5849625007211565 3.700439718141092)

With a measly 4 item collection, I don’t think the reducers are going to provide much speed improvement here but we’d need to use the fold function if we want processing of the collection to be done in parallel.

One for next time!

How do you break a Monolith into Microservices at Scale? This ebook shows strategies and techniques for building scalable and resilient microservices.

Topics:
clojure ,reducer ,functional languages ,functional programming

Published at DZone with permission of

Opinions expressed by DZone contributors are their own.

{{ parent.title || parent.header.title}}

{{ parent.tldr }}

{{ parent.urlSource.name }}