Java low level: Converting between integers and text (part 2)
Java low level: Converting between integers and text (part 2)
Join the DZone community and get the full member experience.
Join For FreeHow do you break a Monolith into Microservices at Scale? This ebook shows strategies and techniques for building scalable and resilient microservices.
Parsing an integer is relatively simple depending on how many checks you make. This loop does almost no validation. The input can multiple '-' signs and the number can overflow. As soon as it reaches a character is does not accept to stops. It is left to the caller to check if this character was a valid separartor.
long num = 0;
boolean negative = false;
while (true) {
byte b = buffer.get();
// if (b >= '0' && b <= '9')
if ((b - ('0' + Integer.MIN_VALUE)) <= 9 + Integer.MIN_VALUE)
num = num * 10 + b - '0';
else if (b == '-')
negative = true;
else
break;
}
return negative ? -num : num;
Note: The expression
(b >= '0' && b <= '9') has been re-written taking advantage of an underflow to turn this into one comparison.
To follow...
Converting floating point numbers to text
From http://vanillajava.blogspot.com/2011/07/java-low-level-converting-between_14.html
How do you break a Monolith into Microservices at Scale? This ebook shows strategies and techniques for building scalable and resilient microservices.
Like This Article? Read More From DZone
Opinions expressed by DZone contributors are their own.
{{ parent.title || parent.header.title}}
{{ parent.tldr }}
{{ parent.linkDescription }}
{{ parent.urlSource.name }}