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Java Quiz: Exception Handling in Java

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Java Quiz: Exception Handling in Java

The latest advanced Java quiz from DZone's resident quizmaster!

· Java Zone ·
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Last Week's Answer: Using Inheritance and Static Methods

int x = 2;
static int s = 3;

MyClass mc = new MyClass();
x=2, s=3;
   super(3)
      this();
          x+=4; x=2+4 =6;
       x += x + 20; // ignore this value because it is a parameter
    x -= 7 = 6-7= -1 
    s += x = 3 -1 = 2     
mc.method(); 
   x+= 7;
   x = -1+7=6;
   super.method();
      x += 35 = 6+35 = 41; // ignore this value, see next step. 
new MyClass(); // returns a new object, the value of x reset to 2.
   x=2, s=2; // the last value of “s” is 2 because it is static.
   super(3)
      this();
          x+=4; x=2+4 =6;
       x += x + 20; //ignore this x because it is a parameter.
    x -= 7 = 6-7=-1
    s += x = 2 -1 = 1

The result is that the code writes "1" to the standard output

This Week's Quiz: Exception Handling in Java

This quiz is aimed at advanced Java programmers.

Purpose

  1. To introduce some tricks and behaviors of Java exceptions.

  2. To train and improve your imagination.

What is written to the standard output as the result of executing the following code?

public class MyClass {

    int x;

    public void method(int i){
        try {
            if(i > 2) {
                i = (1 / 0) + Integer.parseInt("x");
            }else {
                i = Integer.parseInt("x") + (1 / 0);
            }
        }catch(ArithmeticException e) {
            x += 4;
        }catch(RuntimeException e) {
            x += 3;
        }catch(Exception e) {
            x += 5;
        }finally {
            x += 2;
        }
        x ++ ;
    }
    public static void main(String[] args){
        MyClass mc = new MyClass();
        mc.method(3);
        mc.method(2);
        System.out.print(mc.x);
    }
}

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Topics:
java ,exception handling

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