Last Week's Answer

First Method: mc.method(3)

int x = 0;
if(i > 2)
//3 > 2 is true;
i = (1 / 0) + Integer.parseInt("x");
//The first part of this equation is dividing by 0.
//That is why the exception is handled by the “ArithmeticException” block.
x += 4; x = 4; 
//Finally and the last statement are always executed:
x = 4+2+1=7;

Second Method: mc.method(2)

//2 > 2 is false
i = Integer.parseInt("x") + (1 / 0);
//The first part of the exception would be handled in the “RuntimeException” block not in the “ArithmeticException” block. See the RuntimeException hirarchy Java library.
X = 7+3 = 10
//finally and the last statement are always executed, that is why the end result is:
10 + 2 + 1 = 13

This Week's Quiz

Purpose

1. Demonstrating a trick that might distract programmers.

2. Helps to stay focused by programming.

What is written to the standard output as a result of executing the following code?

public class MyClass {

    int x;
    int[] arrayInt = {4,3,0 };

    int methodA(int i, int i2){
        int i3 = i + i2 - 1;
        return(i3 - (2 * i) / x - x / 2);
    }
    int methodB(){
        for(int i:arrayInt) {
            switch(i) {
                case 3:
                    x ++ ;
                case 5:
                    x += 2;
                    break;
                default:
                    x += 3;
                case 0:
                    x += 4;
                case 1:
                    x += 5;
            }
        }
        return x / 2;
    }
    public static void main(String[] args){
        MyClass mc = new MyClass();
        System.out.println("result: " + mc.methodA(mc.methodB(),2));
    }
}

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