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Prime Factor Decomposition of a Number

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Prime Factor Decomposition of a Number

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The following function computes the prime factors (PFs) of an integer.

from math import floor

def factors(n):
 result = []
 for i in range(2,n+1): # test all integers between 2 and n
  s = 0;
  while n/i == floor(n/float(i)): # is n/i an integer?
   n = n/float(i)
   s += 1
  if s > 0:
   for k in range(s):
    result.append(i) # i is a pf s times
   if n == 1:
    return result

# test
print factors(90)

The result will be

[2, 3, 3, 5]

This means that 90 is equal to 2*3*3*5.

 

 

 

Deploying code to production can be filled with uncertainty. Reduce the risks, and deploy earlier and more often. Download this free guide to learn more. Brought to you in partnership with Rollbar.

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