DZone
Thanks for visiting DZone today,
Edit Profile
  • Manage Email Subscriptions
  • How to Post to DZone
  • Article Submission Guidelines
Sign Out View Profile
  • Post an Article
  • Manage My Drafts
Over 2 million developers have joined DZone.
Log In / Join
Refcards Trend Reports
Events Video Library
Refcards
Trend Reports

Events

View Events Video Library

Related

  • A Comprehensive Guide To Working With JSON in JavaScript
  • Streamlining Your Workflow With the Jenkins HTTP Request Plugin: A Guide to Replacing CURL in Scripts
  • JSON-Based Serialized LOB Pattern
  • How To Check for JSON Insecure Deserialization (JID) Attacks With Java

Trending

  • Chaos Engineering Has a Blind Spot. Agentic AI Lives in It.
  • Contract-First Integration: Building Scalable Systems With Flyway, OpenAPI, and Kafka
  • How We Diagnosed a Hidden Scheduler Failure in a Docker Swarm Cluster Serving 2 Million Users
  • Beyond Conversation: Mastering Context with Claude Code Skills and Agents
  1. DZone
  2. Coding
  3. Languages
  4. Groovy Unmarshalling JSON to a Specific Object

Groovy Unmarshalling JSON to a Specific Object

A code snippet to use Groovy's default map-based constructor to convert JSON strings to an object type.

By 
Ravi Isnab user avatar
Ravi Isnab
·
Jan. 25, 16 · Code Snippet
Likes (6)
Comment
Save
Tweet
Share
33.7K Views

Join the DZone community and get the full member experience.

Join For Free

If you have a simple POJO (Plain Old Java Object) or POGO (Plain Old Groovy Object), you can use Groovy's default Map-based constructor to convert the JSON string to an Object type.

package com.example.groovy

import groovy.json.JsonBuilder  
import groovy.json.JsonSlurper  
import groovy.transform.ToString

/**
 * Created by rhasija on 1/15/16.
 */
class JsonToObject {

    public static void main(String[] args) {
        // Person object
        def person = new Person(firstName: "John", lastName: "Doe")
        // Json String
        def personJSON = new JsonBuilder(person).toPrettyString()
        // Json String to Map
        def personMap = new JsonSlurper().parseText(personJSON)
        // using Map to convert to Person object type
        def newPerson = new Person(personMap)

        println(person)
        println(newPerson)

        assert newPerson.firstName.equals(person.firstName)
        assert newPerson.lastName.equals(person.lastName)
    }
}

@ToString
class Person {  
    String firstName
    String lastName
}

Please let me know if you found this helpful. Thanks!

JSON Groovy (programming language) Object (computer science)

Published at DZone with permission of Ravi Isnab. See the original article here.

Opinions expressed by DZone contributors are their own.

Related

  • A Comprehensive Guide To Working With JSON in JavaScript
  • Streamlining Your Workflow With the Jenkins HTTP Request Plugin: A Guide to Replacing CURL in Scripts
  • JSON-Based Serialized LOB Pattern
  • How To Check for JSON Insecure Deserialization (JID) Attacks With Java

Partner Resources

×

Comments

The likes didn't load as expected. Please refresh the page and try again.

  • RSS
  • X
  • Facebook

ABOUT US

  • About DZone
  • Support and feedback
  • Community research

ADVERTISE

  • Advertise with DZone

CONTRIBUTE ON DZONE

  • Article Submission Guidelines
  • Become a Contributor
  • Core Program
  • Visit the Writers' Zone

LEGAL

  • Terms of Service
  • Privacy Policy

CONTACT US

  • 3343 Perimeter Hill Drive
  • Suite 215
  • Nashville, TN 37211
  • [email protected]

Let's be friends:

  • RSS
  • X
  • Facebook