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  4. Groovy Unmarshalling JSON to a Specific Object

Groovy Unmarshalling JSON to a Specific Object

A code snippet to use Groovy's default map-based constructor to convert JSON strings to an object type.

By 
Ravi Isnab user avatar
Ravi Isnab
·
Jan. 25, 16 · Code Snippet
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If you have a simple POJO (Plain Old Java Object) or POGO (Plain Old Groovy Object), you can use Groovy's default Map-based constructor to convert the JSON string to an Object type.

package com.example.groovy

import groovy.json.JsonBuilder  
import groovy.json.JsonSlurper  
import groovy.transform.ToString

/**
 * Created by rhasija on 1/15/16.
 */
class JsonToObject {

    public static void main(String[] args) {
        // Person object
        def person = new Person(firstName: "John", lastName: "Doe")
        // Json String
        def personJSON = new JsonBuilder(person).toPrettyString()
        // Json String to Map
        def personMap = new JsonSlurper().parseText(personJSON)
        // using Map to convert to Person object type
        def newPerson = new Person(personMap)

        println(person)
        println(newPerson)

        assert newPerson.firstName.equals(person.firstName)
        assert newPerson.lastName.equals(person.lastName)
    }
}

@ToString
class Person {  
    String firstName
    String lastName
}

Please let me know if you found this helpful. Thanks!

JSON Groovy (programming language) Object (computer science)

Published at DZone with permission of Ravi Isnab, DZone MVB. See the original article here.

Opinions expressed by DZone contributors are their own.

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  • Streamlining Your Workflow With the Jenkins HTTP Request Plugin: A Guide to Replacing CURL in Scripts
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  • How To Check for JSON Insecure Deserialization (JID) Attacks With Java

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