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If You're Using Java’s Scanner Class for Keyboard Input, You're Doing it Wrong

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If You're Using Java’s Scanner Class for Keyboard Input, You're Doing it Wrong

So, if you're using the Scanner class for keyboard input in Java, you're probably doing it wrong. Check out this post to learn more about the Scanner class.

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Yesterday, I gave my third-year Java students a warm-up exercise. The students were free to use console, Swing, or JavaFX for user input. Most chose a console because they had minimal exposure to GUI coding and that is one of the main topics covered in my course. Within a few minutes, some hands went up in regards to using the Scanner class. Here is a simplified version of what they were trying to do:

public class App {

    public void perform() {

    public void firstScanner() {
        String str = "";
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a string: ");
        if (sc.hasNext()) {
            str = sc.next();
        System.out.println("str = " + str);

    public void secondScanner() {
        int num = 0;
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter a number: ");
        if (sc.hasNextInt()) {
            num = sc.nextInt();
        System.out.println("num = " + num);

    public static void main(String[] args) {
        App app = new App();

Scanner Demo

When this program executes, it asks for the first String but never asks for the int . A run looks like:

Enter a string: 
str = bob
Enter a number: 
num = 0

It never stops to ask for the number and immediately prints out the default value for num. I had never seen this problem before. When I teach an introductory course, I show my students that the Scanner for keyboard input should, in most cases, be a class variable initialized in the constructor. I also must admit that I never close the Scanner object when the keyboard is involved.

You can see that, in the code, the Scanner object is closed in each method. I didn’t think this was a problem, and so I stared at the student’s code for a few minutes and then went to Google. There was not much to be found. Most of the information showed that when using Scanner to access a file, you should close it. Most articles that used Scanner for keyboard input declared the Scanner in a method and closed it at the end of the method. There was one suggestion in a StackOverflow posting that suggested a potential problem with closing Scanner for keyboard input, but it was not definitive.

My next experiment was to remove the close() statements. The Scanner performed as originally expected:

Enter a string: 
str = bob
Enter a number: 
num = 23

So, back to research on Google where I uncovered a fact not mentioned in any JavaDocs or in any article from any source when discussing the Scanner class. If  System.in, a BufferedInputStream from the keyboard, is closed, as happens when the Scanner object is closed, you are closing a System stream that cannot be re-opened. The program must be exited and then re-run to re-establish  System.in.

I thought this was strange and looked deeper into how the keyboard was connected to System.in. This stream is established by private methods in the JVM. I did see suggestions as to how this could be re-established, but I suspect that this code may have never been tested:

Suggestion #1

FileInputStream fdIn = new FileInputStream(FileDescriptor.in);
System.setIn(new BufferedInputStream(fdIn));

Suggestion #2

System.setIn(new FileInputStream(FileDescriptor.in));

Neither worked to re-establish the connection between System.in and the keyboard. If you know a way, then I’d dearly like to know. For now:


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java ,javafx ,scanner ,scanner class ,system in

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