Java SE 7 type inference

I taught an introductory Java session on generics, and of course demonstrated the shorthand introduced in Java SE 7 for instantiating an instance of a generic type:

// Java SE 6
List<Integer> l = new ArrayList<Integer>(); 
// Java SE 7
List<Integer> l = new ArrayList<>();

This inference is very friendly, especially when we get into more complex collections:

// This
Map<String,List<String>> m = new HashMap<String,List<String>>();
// Becomes
Map<String,List<String>> m = new HashMap<>();

Not only the key and value type of the map, but the type of object stored in the collection used for the value type can be inferred.

Of course, sometimes this inference breaks down. It so happens I ran across an interesting example of this. Imagine populating a set from a list, so as to speed up random access and remove duplicates. Something like this will work:

List<String> list = ...; // From somewhere

Set<String> nodup = new HashSet<>(list);

However, this runs into trouble if the list could be null. The HashSetconstructor will not just return an empty set but will throwNullPointerException. So we need to guard against null here. Of course, like all good programmers, we seize the chance to use a ternary operator because ternary operators are cool.

List<String> list = ...; // From somewhere

Set<String> nodup = (null == list) ? new HashSet<>() :
                      new HashSet<>(list);

And here’s where inference breaks down. Because this is no longer a simple assignment, the statement new HashSet<>() can no longer use the left hand side in order to infer the type. As a result, we get that friendly error message, “Type mismatch: cannot convert from HashSet<capture#1-of ? extends Object> to Set<String>”. What’s especially interesting is that inference breaks down even though the compiler knows that an object of typeSet<String> is what is needed in order to gain agreement of types. The rules for inference are written to be conservative by doing nothing when an invalid inference might cause issues, while the compiler’s type checking is also conservative in what it considers to be matching types.

Also interesting is that we only get that error message for the new HashSet<>(). The statement new HashSet<>(list) that uses the list to populate the set works just fine. This is because the inference is completed using the listparameter. Here’s the constructor:

public class HashSet<E> extends ... implements ...
{
  ...
  public HashSet(Collection<? extends E> c) { ... }
  ...
}

The List<String> that we pass in gets captured as Collection<? extends String> and this means that E is bound to String, so all is well.

As a result, we wind up with the perfectly valid, if a little funny looking:

List<String> list = ...; // From somewhere

Set<String> nodup = (null == list) ? new HashSet<String>() :
                      new HashSet<>(list);

Of course, I imagine most Java programmers do what I do, which is try to use the shortcut and then add the type parameter when the compiler complains. Following the rule about not meddling in the affairs of compilers (subtle; quick to anger), normally I would just fix it without trying very hard to understand why the compiler liked or didn’t like things done in a certain way. But this one was such a strange case I figured it was worth a longer look.