We will be working with two tables — customer and orders — that we imported in my sqoop import article, and we'll perform the following joins:

1. INNER JOIN – Select records that have matching values in both tables.
2. LEFT JOIN (LEFT OUTER JOIN) – Returns all the values from the left table, plus the matched values from the right table, or NULL in case of no matching join predicate
3. RIGHT JOIN (RIGHT OUTER JOIN) A RIGHT JOIN returns all the values from the right table, plus the matched values from the left table, or NULL in case of no matching join predicate
4. FULL JOIN (FULL OUTER JOIN) – Selects all records that match either left or right table records.
5. LEFT SEMI JOIN: Only returns the records from the left-hand table. Hive doesn’t support IN subqueries so you can’t do

SELECT * FROM TABLE_A WHERE TABLE_A.ID IN (SELECT ID FROM TABLE_B);

Customer Table

Hive Tip: to print column headers in command line:

hive> set hive.cli.print.header=true;

hive> select * from customers;
 OK
 customers.id customers.name
 1 John
 2 Kevin
 19 Alex
 3 Mark
 4 Jenna
 5 Robert
 6 Zoya
 7 Sam
 8 George
 9 Peter

Orders Table:

hive> select * from orders;
 OK
 order_id orders.order_date orders.customer_id orders.amount
 101 2016-01-01 7 3540
 102 2016-03-01 1 240
 103 2016-03-02 6 2340
 104 2016-02-12 3 5000
 105 2016-02-12 3 5500
 106 2016-02-14 9 3005
 107 2016-02-14 1 20
 108 2016-02-29 2 2000
 109 2016-02-29 3 2500
 110 2016-02-27 1 200

INNER JOIN

Select records that have matching values in both tables.

hive> select c.id, c.name, o.order_date, o.amount from customers c inner join orders o ON (c.id = o.customer_id);

Output

c.id c.name o.order_date o.amount
 7 Sam 2016-01-01 3540
 1 John 2016-03-01 240
 6 Zoya 2016-03-02 2340
 3 Mark 2016-02-12 5000
 3 Mark 2016-02-12 5500
 9 Peter 2016-02-14 3005
 1 John 2016-02-14 20
 2 Kevin 2016-02-29 2000
 3 Mark 2016-02-29 2500
 1 John 2016-02-27 200

LEFT JOIN (LEFT OUTER JOIN)

Returns all the values from the left table, plus the matched values from the right table, or NULL in case of no matching join predicate

hive> select c.id, c.name, o.order_date, o.amount from customers c left outer join orders o ON (c.id = o.customer_id);

Output
 c.id    c.name    o.order_date    o.amount
 1    John    2016-03-01    240
 1    John    2016-02-14    20
 1    John    2016-02-27    200
 2    Kevin    2016-02-29    2000
 19    Alex    NULL    NULL
 3    Mark    2016-02-12    5000
 3    Mark    2016-02-12    5500
 3    Mark    2016-02-29    2500
 4    Jenna    NULL    NULL
 5    Robert    NULL    NULL
 6    Zoya    2016-03-02    2340
 7    Sam    2016-01-01    3540
 8    George    NULL    NULL
 9    Peter    2016-02-14    3005
 Time taken: 40.462 seconds, Fetched: 14 row(s)

RIGHT JOIN (RIGHT OUTER JOIN)

Returns all the values from the right table, plus the matched values from the left table, or NULL in case of no matching join predicate

hive> select c.id, c.name, o.order_date, o.amount from customers c left outer join orders o ON (c.id = o.customer_id);

Output
 c.id    c.name    o.order_date    o.amount
 7    Sam    2016-01-01    3540
 1    John    2016-03-01    240
 6    Zoya    2016-03-02    2340
 3    Mark    2016-02-12    5000
 3    Mark    2016-02-12    5500
 9    Peter    2016-02-14    3005
 1    John    2016-02-14    20
 2    Kevin    2016-02-29    2000
 3    Mark    2016-02-29    2500
 1    John    2016-02-27    200

FULL JOIN (FULL OUTER JOIN)

Selects all records that match either left or right table records.

hive> select c.id, c.name, o.order_date, o.amount from customers c full outer join orders o ON (c.id = o.customer_id);

Output

c.id c.name o.order_date o.amount
 1 John 2016-02-27 200
 1 John 2016-02-14 20
 1 John 2016-03-01 240
 19 Alex NULL NULL
 2 Kevin 2016-02-29 2000
 3 Mark 2016-02-29 2500
 3 Mark 2016-02-12 5500
 3 Mark 2016-02-12 5000
 4 Jenna NULL NULL
 5 Robert NULL NULL
 6 Zoya 2016-03-02 2340
 7 Sam 2016-01-01 3540
 8 George NULL NULL
 9 Peter 2016-02-14 3005

LEFT SEMI JOIN

Find all the customers where at least one order exist or find all customer who has placed an order.

hive> select *  from customers  left semi join orders  ON 
(customers.id = orders.customer_id);

OUTPUT

customers.id    customers.name
1    John
2    Kevin
3    Mark
6    Zoya
7    Sam
9    Peter
Time taken: 56.362 seconds, Fetched: 6 row(s)

That’s it for this article. I hope you find this useful, thank you for reading!